| ⇦ | 
| ⇨ |
The work done during the expansion of a gas from a volume of 4 dm³ to 6 dm³ against a constant external pressure of 3 atm is (1atm = 101.32 J)
Options
(a) -6 J
(b) -608 J
(c) ⁺304 J
(d) -304 J
Correct Answer:
-608 J
Explanation:
Work = -P(ext) x volume change =
-3 x 101.32 x (6 – 4)
= -6 x 101.32 = -607.92 J = -608 J
Related Questions: - Borax is used as a cleansing agent because on dissolving in water it gives
- The oxidation number of oxygen in O₂PtF₆ is
- ΔH°f (298 K) of methanol is given by the chemical equation
- Which of the following gives propyne on hydrolysis
- Chemical properties of lithium and magnesium are similar because
Topics: Thermodynamics
(179)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Borax is used as a cleansing agent because on dissolving in water it gives
- The oxidation number of oxygen in O₂PtF₆ is
- ΔH°f (298 K) of methanol is given by the chemical equation
- Which of the following gives propyne on hydrolysis
- Chemical properties of lithium and magnesium are similar because
Topics: Thermodynamics (179)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply