| ⇦ | 
| ⇨ |
The work done during the expansion of a gas from a volume of 4 dm³ to 6 dm³ against a constant external pressure of 3 atm is (1atm = 101.32 J)
Options
(a) -6 J
(b) -608 J
(c) ⁺304 J
(d) -304 J
Correct Answer:
-608 J
Explanation:
Work = -P(ext) x volume change =
-3 x 101.32 x (6 – 4)
= -6 x 101.32 = -607.92 J = -608 J
Related Questions: - In the Dumas method of estimation of nitrogen,the nitrogen in the organic compound
- Which one of the following is a non-benzenoid aromatic compound
- Which of the following has ability to release bromine from potassium bromide
- Schiff’s reagent is
- The catalyst used in the manufacture of H₂SO₄ by contact process is
Topics: Thermodynamics
(179)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In the Dumas method of estimation of nitrogen,the nitrogen in the organic compound
- Which one of the following is a non-benzenoid aromatic compound
- Which of the following has ability to release bromine from potassium bromide
- Schiff’s reagent is
- The catalyst used in the manufacture of H₂SO₄ by contact process is
Topics: Thermodynamics (179)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply