| ⇦ | 
| ⇨ |
The weight of one molecule of a compound C₆₀H₁₂₂ is
Options
(a) 1.2 x 10⁻²° gram
(b) 1.4 x 10⁻²¹ gram
(c) 5.025 x 10²³ gram
(d) 6.023 x 10²³ gram
Correct Answer:
1.4 x 10⁻²¹ gram
Explanation:
Atomic Mass of C=12
Atomic Mass of H=1
Molecular Weight of C₆₀H₁₂₂ = 12 x 60 + 122 = 842
Weight of 1 molecule = Mol Wt of C₆₀H₁₂₂ / Avagadro No
=842 / 6.023 x 10²³ = 1.4 x 10⁻²¹ g
Related Questions: - Sodium Hydroxide reacts with Zinc to form
- Distribution law was given by
- Ksp of CaSO₄.5H₂O is 9 ˣ 10⁻⁶, find the volume for 1g of CaSO₄ (M.wt, = 136)
- 0.45 g acid of molecular weight 90 was neutralise by 20 mL of 0.5 N KOH
- A mixture of champhor and benzoic acid can be separated by
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Basic Concepts of Chemistry
(94)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Sodium Hydroxide reacts with Zinc to form
- Distribution law was given by
- Ksp of CaSO₄.5H₂O is 9 ˣ 10⁻⁶, find the volume for 1g of CaSO₄ (M.wt, = 136)
- 0.45 g acid of molecular weight 90 was neutralise by 20 mL of 0.5 N KOH
- A mixture of champhor and benzoic acid can be separated by
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply