| ⇦ |
| ⇨ |
The weight of iron which will be converted into its oxide(Fe₃O₄) by the action of 18 g of steam on it will be (at. wt. of Fe=56)
Options
(a) 168 g
(b) 84 g
(c) 42 g
(d) 21 g
Correct Answer:
42 g
Explanation:
3Fe + 4H₂O → Fe₃O₄ + 4H₂
3x 56 g 4x 18 g
= 168 g = 72 g
72 g steam requries Fe= 168 g
18 g steam requires Fe= 168x 18/72
= 42 g
Related Questions: - 6.02 x 10²° molecules of urea are present in 100 mL of its solution
- Fine the magnetic moment of a divalent ion in aqueous solution if its atomic
- Which of the following statement concerning lanthanides elements is fals
- An orbital in which n = 4 and l = 2 is expressed by
- The increasing order of atomic radius for the elements Na, Rb, K and Mg is
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Basic Concepts of Chemistry
(94)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- 6.02 x 10²° molecules of urea are present in 100 mL of its solution
- Fine the magnetic moment of a divalent ion in aqueous solution if its atomic
- Which of the following statement concerning lanthanides elements is fals
- An orbital in which n = 4 and l = 2 is expressed by
- The increasing order of atomic radius for the elements Na, Rb, K and Mg is
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply