| ⇦ |
| ⇨ |
The wavelength of the first line of Lyman series for hydrogen atom is equal to that of the second line of Balmer series for a hydrogen like ion. The atomic number Z of hydrogen like ion is
Options
(a) 3
(b) 4
(c) 1
(d) 2
Correct Answer:
2
Explanation:
For first line of Lyman series of hydrogen
hc/λ₁ = Rhc (1/1² – 1/2²)
For second line of Balmer series of hydrogen like on
hc/λ₂ = Z²Rhc (1/2² – 1/4²)
By eq. λ₁ = λ₂
(1/1 – 1/2) = Z² (1/4 – 1/16) or Z = 2
Related Questions: - The coefficient of friction between the tyres and the road is 0.25. The maximum speed
- CO₂ laser uses
- At what angle should the two forces 2P and √2 P act,so that the resultant force is P√10?
- When 4 A current flows for 2 min in an electroplating experiment,
- If, an electron in hydrogen atom jumps from an orbit of level n=3 to an orbit
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The coefficient of friction between the tyres and the road is 0.25. The maximum speed
- CO₂ laser uses
- At what angle should the two forces 2P and √2 P act,so that the resultant force is P√10?
- When 4 A current flows for 2 min in an electroplating experiment,
- If, an electron in hydrogen atom jumps from an orbit of level n=3 to an orbit
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply