| ⇦ |
| ⇨ |
The values of heat of formation of SO₂ and SO₃ are -298.2 kJ and -98.2 kJ. The heat of formation of this reaction will be SO₂ + (1/2)O₂ → SO₃
Options
(a) 200 kJ
(b) -356.2 kJ
(c) -200 kJ
(d) -396.2 kJ
Correct Answer:
200 kJ
Explanation:
Values of heat formation of SO₂ = -298.2 kJ and that of SO₃ = -98.2 kJ.
Therefore S(s) + O₂(g) → SO₂(g) , ΔH = -298.2 kJ ..(i)
and S(s) + (3/2)O₂(g) → SO₃(g), ΔH = -98.2 kJ ..(ii)
Subtracting equation, (i) from (ii), we get,
SO₂ + 1/2O₂ → SO₃. ΔH = -98.2 – (-298.2) = 200 kJ.
Related Questions: - In an isobaric process,when temperature changes from T₁ to T₂, ΔS is equal to
- Choose the incorrect statement in the following
- Which of the following salts will give highest pH in water
- Zeolite used to soften hardness of water is, hydrated
- The entropy change in the conversion of a solid into its different states
Topics: Thermodynamics
(179)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In an isobaric process,when temperature changes from T₁ to T₂, ΔS is equal to
- Choose the incorrect statement in the following
- Which of the following salts will give highest pH in water
- Zeolite used to soften hardness of water is, hydrated
- The entropy change in the conversion of a solid into its different states
Topics: Thermodynamics (179)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply