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The values of heat of formation of SO₂ and SO₃ are -298.2 kJ and -98.2 kJ. The heat of formation of this reaction will be SO₂ + (1/2)O₂ → SO₃
Options
(a) 200 kJ
(b) -356.2 kJ
(c) -200 kJ
(d) -396.2 kJ
Correct Answer:
200 kJ
Explanation:
Values of heat formation of SO₂ = -298.2 kJ and that of SO₃ = -98.2 kJ.
Therefore S(s) + O₂(g) → SO₂(g) , ΔH = -298.2 kJ ..(i)
and S(s) + (3/2)O₂(g) → SO₃(g), ΔH = -98.2 kJ ..(ii)
Subtracting equation, (i) from (ii), we get,
SO₂ + 1/2O₂ → SO₃. ΔH = -98.2 – (-298.2) = 200 kJ.
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Topics: Thermodynamics
(179)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An organic compound gives Molisch’s test as well as Benedict’s test.
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Topics: Thermodynamics (179)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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