The value of workdone for rotating a magnet of magnetic moment M by an angle θ in external magnetic field H is given by
Options
(a) MH cos θ
(b) 2MH sin²(θ/2)
(c) MH sin θ
(d) MH (1-sin²θ)
Correct Answer:
MH cos θ
Explanation:
MH (1 – cos θ) = work done
.·. W = MH [1 – 1 + 2 sin² (θ / 2)] = 2MH sin² (θ / 2)
View Comments (1)
B is the right option