| ⇦ | 
| ⇨ |
The value of workdone for rotating a magnet of magnetic moment M by an angle θ in external magnetic field H is given by
Options
(a) MH cos θ
(b) 2MH sin²(θ/2)
(c) MH sin θ
(d) MH (1-sin²θ)
Correct Answer:
MH cos θ
Explanation:
MH (1 – cos θ) = work done
.·. W = MH [1 – 1 + 2 sin² (θ / 2)] = 2MH sin² (θ / 2)
Related Questions: - Pure Si at 500 K has equal number of electron (nₑ) and hole (nₕ) concentrations
- If an electron in a hydrogen atom jumps from the 3rd orbit to the 2nd orbit, it emits
- The motion of a particle along a straight line is described by equation
- Three blocks A,B and C of masses 4 kg, 2 kg and 1 kg respectively are in contact
- An object is 8 cm high. It is desired to form a real image 4 cm high at 60 cm from
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Pure Si at 500 K has equal number of electron (nₑ) and hole (nₕ) concentrations
- If an electron in a hydrogen atom jumps from the 3rd orbit to the 2nd orbit, it emits
- The motion of a particle along a straight line is described by equation
- Three blocks A,B and C of masses 4 kg, 2 kg and 1 kg respectively are in contact
- An object is 8 cm high. It is desired to form a real image 4 cm high at 60 cm from
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
B is the right option