⇦ | ⇨ |
The value of workdone for rotating a magnet of magnetic moment M by an angle θ in external magnetic field H is given by
Options
(a) MH cos θ
(b) 2MH sin²(θ/2)
(c) MH sin θ
(d) MH (1-sin²θ)
Correct Answer:
MH cos θ
Explanation:
MH (1 – cos θ) = work done
.·. W = MH [1 – 1 + 2 sin² (θ / 2)] = 2MH sin² (θ / 2)
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Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A common emitter amplifier is designed with n-p-n transistor (α=0.99).
- Three identical spheres, each of mass 3 kg are placed touching each other
- A magnetic force acting on a charged particle of charge -2µC in a magnetic field of 2T
- Two parallel beams of positron moving in the same direction will
- A particle in simple harmonic motion is described by the displacement function
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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B is the right option