The total energy of an electron in the first excited state of hydrogen atom

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The total energy of an electron in the first excited state of hydrogen atom is about -3.4 eV. Its kinetic energy in this state is

Options

(a) 3.4 eV
(b) 6.8 eV
(c) -3.4 eV
(d) -6.8 eV

Correct Answer:

3.4 eV

Explanation:

KE. = |(1/2) P.E.|
But P.E. is negavite
.·. Total energy = |(1/2) P.E.| – P.E. = – P.E. / 2 = – 3.4 eV
.·. K.E. = + 3.4 eV

Related Questions:

1. A ball is moving in a circular path of radius 5 m.If tangential acceleration
2. Two bodies A and B have masses 20 Kg and 5 Kg respectively. Each one is acted
3. According to Bohr model of hydrogen atom, only those orbits are permissible
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5. The instantaneous angular position of a point on a rotating wheel is given by

Topics: Atoms and Nuclei (136)
Subject: Physics (2479)

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