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The string of a pendulum is horizontal.The mass of bob attached to it is m.Now, the string is released.The tension in the string in the lowest position is
Options
(a) mg
(b) 2 mg
(c) 3 mg
(d) 4 mg
Correct Answer:
3 mg
Explanation:
When string is released, then according to conservation of energy,
(1/2) mv² = mgh
v² = 2gh = 2gR
Now, when it is at the bottom,
T – mg cos 0² = mv²/R
or T – mg = (m/R)(2gR)
T = mg + 2mg = 3mg.
Related Questions: - The maximum particle velocity in a wave motion is half the wave velocity.
- When 4 A current flows for 2 min in an electroplating experiment,
- Two blocks of masses m₁=4 kg and m₂= 2kg are connected to the ends of a string
- If the error in the measurement of momentum of particle is (+100%)
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The maximum particle velocity in a wave motion is half the wave velocity.
- When 4 A current flows for 2 min in an electroplating experiment,
- Two blocks of masses m₁=4 kg and m₂= 2kg are connected to the ends of a string
- If the error in the measurement of momentum of particle is (+100%)
- A hollow sphere of radius 0.1m has a charge of 5×10⁻⁸C. The potential
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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