| ⇦ | 
| ⇨ |
The string of a pendulum is horizontal.The mass of bob attached to it is m.Now, the string is released.The tension in the string in the lowest position is
Options
(a) mg
(b) 2 mg
(c) 3 mg
(d) 4 mg
Correct Answer:
3 mg
Explanation:
When string is released, then according to conservation of energy,
(1/2) mv² = mgh
v² = 2gh = 2gR
Now, when it is at the bottom,
T – mg cos 0² = mv²/R
or T – mg = (m/R)(2gR)
T = mg + 2mg = 3mg.
Related Questions: - 300j work is done in sliding a 2kg block up an inclined plane of height 10m
- The volume of a nucleus is directly proportional to
- We get Balmer series when electron comes from
- The p-type semiconductor is
- A thin ring of radius R meter has charge q coulomb uniformly spread on it
Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- 300j work is done in sliding a 2kg block up an inclined plane of height 10m
- The volume of a nucleus is directly proportional to
- We get Balmer series when electron comes from
- The p-type semiconductor is
- A thin ring of radius R meter has charge q coulomb uniformly spread on it
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply