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The string of a pendulum is horizontal.The mass of bob attached to it is m.Now, the string is released.The tension in the string in the lowest position is
Options
(a) mg
(b) 2 mg
(c) 3 mg
(d) 4 mg
Correct Answer:
3 mg
Explanation:
When string is released, then according to conservation of energy,
(1/2) mv² = mgh
v² = 2gh = 2gR
Now, when it is at the bottom,
T – mg cos 0² = mv²/R
or T – mg = (m/R)(2gR)
T = mg + 2mg = 3mg.
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A and B are two vectors and θ is the angle between them ,if |A x B|=√3(A.B),the value of θ
- Two capacitors 3μF and 4μF, are individually charged across a 6 V battery.
- An unpolarised beam of intensity I is incident on a pair of nicols making an angle
- A stone thrown into still water, creates a circular wave pattern moving radially
- Two closed pipes produce 10 beats per second when emitting their fundamental nodes.
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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