| ⇦ | 
| ⇨ |
The string of a pendulum is horizontal.The mass of bob attached to it is m.Now, the string is released.The tension in the string in the lowest position is
Options
(a) mg
(b) 2 mg
(c) 3 mg
(d) 4 mg
Correct Answer:
3 mg
Explanation:
When string is released, then according to conservation of energy,
(1/2) mv² = mgh
v² = 2gh = 2gR
Now, when it is at the bottom,
T – mg cos 0² = mv²/R
or T – mg = (m/R)(2gR)
T = mg + 2mg = 3mg.
Related Questions: - An electron in potentiometer experiences a force 2.4×10⁻¹⁹N. The length of potentiometer
- A paramagnetic sample shows a net magnetisation of 0.8 Am⁻¹, when placed
- A dust packet is dropped from 5th storey of a multi-storeyed building
- Copper of fixed volume V is drawn into wire of length l. When this wire is subjected
- The electric potential at a point (x,y,z) is given by V = – x²y – xz³ + 4.
Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An electron in potentiometer experiences a force 2.4×10⁻¹⁹N. The length of potentiometer
- A paramagnetic sample shows a net magnetisation of 0.8 Am⁻¹, when placed
- A dust packet is dropped from 5th storey of a multi-storeyed building
- Copper of fixed volume V is drawn into wire of length l. When this wire is subjected
- The electric potential at a point (x,y,z) is given by V = – x²y – xz³ + 4.
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply