| ⇦ |
| ⇨ |
The string of a pendulum is horizontal.The mass of bob attached to it is m.Now, the string is released.The tension in the string in the lowest position is
Options
(a) mg
(b) 2 mg
(c) 3 mg
(d) 4 mg
Correct Answer:
3 mg
Explanation:
When string is released, then according to conservation of energy,
(1/2) mv² = mgh
v² = 2gh = 2gR
Now, when it is at the bottom,
T – mg cos 0² = mv²/R
or T – mg = (m/R)(2gR)
T = mg + 2mg = 3mg.
Related Questions: - A satellite of mass m revolves around the earth of radius R at a height x from
- In Bohr model of hydrogen atom, the force on the electron depends on the principal
- The dimensions of latent heat are
- A coil of 40 henry inductance is connected in series with a resistance of 8 ohm
- The radius of a planet is twice the radius of earth. Both have almost
Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A satellite of mass m revolves around the earth of radius R at a height x from
- In Bohr model of hydrogen atom, the force on the electron depends on the principal
- The dimensions of latent heat are
- A coil of 40 henry inductance is connected in series with a resistance of 8 ohm
- The radius of a planet is twice the radius of earth. Both have almost
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply