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The speed of an electron having a wavelength of 10⁻¹⁰ m is
Options
(a) 6.26×10⁶ m/s
(b) 5.25 x10⁶ m/s
(c) 7.25×10⁶ m/s
(d) 4.24×10⁶ m/s
Correct Answer:
7.25×10⁶ m/s
Explanation:
λ = h / momentum = h / mv
v = h / mλ = 6.6 × 10⁻³⁴ / (9 × 10⁻³¹) × 10⁻¹°
v = 7.25 × 10⁶ ms⁻¹
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- If, an electron in hydrogen atom jumps from an orbit of level n=3 to an orbit
- Time taken by light to cross a glass slab of thickness 4 mm and refractive index 3 is
- A very small circular loop of radius a is initially (at t=0) coplanar and concentric
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P=h/lamba…..1equ
P= momentum
H=Planck’s constant
Lamba= wavelength
And
P=MV…..2 equ
M= mass
V= speed
Put 2 in 1
MV=h/lamba
9.1×10^-31*v=6.6×10^-34/10^-10
By solving u get the value of v
V=0.725*10^7=7.25*10^6