| ⇦ | 
| ⇨ |
The specific charge of a proton is 9.6×10⁷ C/kg. The specific charge of an alpha particle will be
Options
(a) 9.6 x 10⁷ C kg⁻¹
(b) 19.2 x 10⁷ C kg⁻¹
(c) 4.8 x 10⁷ C kg⁻¹
(d) 2.4 x 10⁷ C kg⁻¹
Correct Answer:
4.8 x 10⁷ C kg⁻¹
Explanation:
For proton, specific charge = e / m = 9.6 × 10⁷ C kg⁻¹
For alpha particle, specific charge = 2e / 4m = 1e / 2m
= (1/2) × 9.6 × 10⁷ = 4.8 × 10⁷ C kg⁻¹
Related Questions: - A proton is moving in a uniform magnetic field B in a circular path of radius a
- For photoelectric emission to take place
- The value of n so that vectors 2i+3j-2k, 5i+nj+k and -i+2j+3k may be coplanar,will be
- An amplifier has a voltage gain Av=1000. The voltage gain in dB is
- A transformer is used to light a 100 W and 110 V lamp from a 220 V mains.
Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A proton is moving in a uniform magnetic field B in a circular path of radius a
- For photoelectric emission to take place
- The value of n so that vectors 2i+3j-2k, 5i+nj+k and -i+2j+3k may be coplanar,will be
- An amplifier has a voltage gain Av=1000. The voltage gain in dB is
- A transformer is used to light a 100 W and 110 V lamp from a 220 V mains.
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply