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The specific charge of a proton is 9.6×10⁷ C/kg. The specific charge of an alpha particle will be
Options
(a) 9.6 x 10⁷ C kg⁻¹
(b) 19.2 x 10⁷ C kg⁻¹
(c) 4.8 x 10⁷ C kg⁻¹
(d) 2.4 x 10⁷ C kg⁻¹
Correct Answer:
4.8 x 10⁷ C kg⁻¹
Explanation:
For proton, specific charge = e / m = 9.6 × 10⁷ C kg⁻¹
For alpha particle, specific charge = 2e / 4m = 1e / 2m
= (1/2) × 9.6 × 10⁷ = 4.8 × 10⁷ C kg⁻¹
Related Questions: - The Davisson- Germer experiment is the direct evidence of
- A device which converts electrical energy into mechanical energy is
- Zenor diode is used for
- In a uniform circular motion,
- The drift velocity does not depend upon
Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The Davisson- Germer experiment is the direct evidence of
- A device which converts electrical energy into mechanical energy is
- Zenor diode is used for
- In a uniform circular motion,
- The drift velocity does not depend upon
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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