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The solubility product of a sparingly soluble salt AX₂ is 3.2 ˣ 10⁻¹¹.Its solubility (in mol/L)is
Options
(a) 5.6 ˣ 10⁻⁶
(b) 3.1 ˣ 10⁻⁴
(c) 2 ˣ 10⁻⁴
(d) 4 ˣ 10⁻⁴
Correct Answer:
2 ˣ 10⁻⁴
Explanation:
K(sp) = 3.2×10⁻¹¹.
AX₂ ⇌ A² + 2X⁻
K(sp) = sx(2s)² = 4s³; i.e) 3.2×10⁻¹¹=4s³. (or) s³ = 0.8×10⁻¹¹
= 8×10⁻¹².
Therefore s = 2×10⁻⁴.
Related Questions: - The charge on the central metal ion in the complex[Ni(CO)₄] is
- The stability of +1 oxidation state increases in the sequence:
- The equivalent weight of H₃PO₂, when it disproportionates into PH₃ and H₃PO₃ is
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Topics: Equilibrium
(104)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The charge on the central metal ion in the complex[Ni(CO)₄] is
- The stability of +1 oxidation state increases in the sequence:
- The equivalent weight of H₃PO₂, when it disproportionates into PH₃ and H₃PO₃ is
- The compressibility factor of an ideal gas is
- What is the product of the reaction of phenol with CHCl₃ in aqueous NaOH
Topics: Equilibrium (104)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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