The solubility product of a sparingly soluble salt AX₂ is 3.2 ˣ 10⁻¹¹.

The Solubility Product Of A Sparingly Soluble Salt Ax Is Chemistry Question

The solubility product of a sparingly soluble salt AX₂ is 3.2 ˣ 10⁻¹¹.Its solubility (in mol/L)is

Options

(a) 5.6 ˣ 10⁻⁶
(b) 3.1 ˣ 10⁻⁴
(c) 2 ˣ 10⁻⁴
(d) 4 ˣ 10⁻⁴

Correct Answer:

2 ˣ 10⁻⁴

Explanation:

K(sp) = 3.2×10⁻¹¹.
AX₂ ⇌ A² + 2X⁻

K(sp) = sx(2s)² = 4s³; i.e) 3.2×10⁻¹¹=4s³. (or) s³ = 0.8×10⁻¹¹
= 8×10⁻¹².
Therefore s = 2×10⁻⁴.

Related Questions:

  1. In a cubic cell,the contribution of an atom at a face of the unit cell is
  2. CF₂ = CF₂ is monomer of
  3. Rate constants of some reaction are given below. predict which one indicates
  4. The metal used to recover copper from a solution of copper sulphate is
  5. Which will show geometrical isomerism

Topics: Equilibrium (104)
Subject: Chemistry (2512)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

Be the first to comment

Leave a Reply

Your email address will not be published.


*