The solubility of CuBr is 2 ˣ 10⁻⁴ mol/L at 25⁰C. The Ksp value for CuBr is

The Solubility Of Cubr Is 2 10 Moll At Chemistry Question

The solubility of CuBr is 2 ˣ 10⁻⁴ mol/L at 25⁰C. The Ksp value for CuBr is

Options

(a) 4 ˣ 10⁻⁸ mol² L⁻²
(b) 4 ˣ 10⁻⁴mol² L⁻²
(c) 4 ˣ 10⁻¹¹mol² L⁻²
(d) 4 ˣ 10⁻¹⁵mol² L⁻²

Correct Answer:

4 ˣ 10⁻⁸ mol² L⁻²

Explanation:

CuBr → Cu⁺ + Br⁻,
Solubility of CuBr is 2×10⁻⁴ mol L⁻¹ ,
therefore, solubility of Cu⁺ = Br⁻ = 2*10⁻⁴ mol L⁻¹ .
⇒ Solubility product = 2*10⁻⁴ * 2 * 10⁻⁴, 4*10⁻⁸ mol²L⁻².

Related Questions:

  1. The density of methane (CH₄) at 2.0 atmospheric pressure and 27⁰C is
  2. Consider the modes of transformations of a gas from state ‘A’ to state ‘B’
  3. At 0K, (i) ¹²C and (ii) a mixture of ¹²C and ¹⁴C will
  4. Hofmann bromamide reaction is used to prepare
  5. 20.0 g of a magnesium carbonate sample decomposes on heating to give carbon dioxide

Topics: Equilibrium (104)
Subject: Chemistry (2512)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

Be the first to comment

Leave a Reply

Your email address will not be published.


*