The solubility of CuBr is 2 ˣ 10⁻⁴ mol/L at 25⁰C. The Ksp value for CuBr is

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The solubility of CuBr is 2 ˣ 10⁻⁴ mol/L at 25⁰C. The Ksp value for CuBr is

Options

(a) 4 ˣ 10⁻⁸ mol² L⁻²
(b) 4 ˣ 10⁻⁴mol² L⁻²
(c) 4 ˣ 10⁻¹¹mol² L⁻²
(d) 4 ˣ 10⁻¹⁵mol² L⁻²

Correct Answer:

4 ˣ 10⁻⁸ mol² L⁻²

Explanation:

CuBr → Cu⁺ + Br⁻,
Solubility of CuBr is 2×10⁻⁴ mol L⁻¹ ,
therefore, solubility of Cu⁺ = Br⁻ = 2*10⁻⁴ mol L⁻¹ .
⇒ Solubility product = 2*10⁻⁴ * 2 * 10⁻⁴, 4*10⁻⁸ mol²L⁻².

Related Questions:

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Topics: Equilibrium (104)
Subject: Chemistry (2512)

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