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The solubility of CuBr is 2 ˣ 10⁻⁴ mol/L at 25⁰C. The Ksp value for CuBr is
Options
(a) 4 ˣ 10⁻⁸ mol² L⁻²
(b) 4 ˣ 10⁻⁴mol² L⁻²
(c) 4 ˣ 10⁻¹¹mol² L⁻²
(d) 4 ˣ 10⁻¹⁵mol² L⁻²
Correct Answer:
4 ˣ 10⁻⁸ mol² L⁻²
Explanation:
CuBr → Cu⁺ + Br⁻,
Solubility of CuBr is 2×10⁻⁴ mol L⁻¹ ,
therefore, solubility of Cu⁺ = Br⁻ = 2*10⁻⁴ mol L⁻¹ .
⇒ Solubility product = 2*10⁻⁴ * 2 * 10⁻⁴, 4*10⁻⁸ mol²L⁻².
Related Questions: - The correct statement regarding defects in crystalline solids is
- Carbogen is
- Which of the following compounds is formed when benzamide is heated with
- Equivalent conductances of Ba²⁺ and Cl⁻ ions are 127 and 76 ohm⁻¹ cm⁻¹ eq⁻¹
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Topics: Equilibrium
(104)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The correct statement regarding defects in crystalline solids is
- Carbogen is
- Which of the following compounds is formed when benzamide is heated with
- Equivalent conductances of Ba²⁺ and Cl⁻ ions are 127 and 76 ohm⁻¹ cm⁻¹ eq⁻¹
- Bhor’s theory is applicable to
Topics: Equilibrium (104)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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