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The solubility of CuBr is 2 ˣ 10⁻⁴ mol/L at 25⁰C. The Ksp value for CuBr is
Options
(a) 4 ˣ 10⁻⁸ mol² L⁻²
(b) 4 ˣ 10⁻⁴mol² L⁻²
(c) 4 ˣ 10⁻¹¹mol² L⁻²
(d) 4 ˣ 10⁻¹⁵mol² L⁻²
Correct Answer:
4 ˣ 10⁻⁸ mol² L⁻²
Explanation:
CuBr → Cu⁺ + Br⁻,
Solubility of CuBr is 2×10⁻⁴ mol L⁻¹ ,
therefore, solubility of Cu⁺ = Br⁻ = 2*10⁻⁴ mol L⁻¹ .
⇒ Solubility product = 2*10⁻⁴ * 2 * 10⁻⁴, 4*10⁻⁸ mol²L⁻².
Related Questions: - What is the pH of 0.01 M glycine solution? For glycine, Ka₁ = 4.5 ˣ 10⁻³
- The wrong statements about glycerol is
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Topics: Equilibrium
(104)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- What is the pH of 0.01 M glycine solution? For glycine, Ka₁ = 4.5 ˣ 10⁻³
- The wrong statements about glycerol is
- Which of the following is not a cheracteristic of equilibrium
- Fibre reactive dyes are the derivatives of
- In which cell the free energy of a chemical reaction is directly converted into
Topics: Equilibrium (104)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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