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The shape of IF₇ molecule is
Options
(a) octahedral
(b) trigonal bipyramidal
(c) tetrahedral
(d) pentagonal bipyramidal
Correct Answer:
pentagonal bipyramidal
Explanation:
Number of hybrid orbitals,
H = 1/2 [V + M + A – C]
H = 1/2 [7 + 7 + 0 – 0]
Thus, thehybridisation of IF₇ is sp³d³ and its geometry is pentagonal bypyraminal.
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