| ⇦ |
| ⇨ |
The shape of IF₇ molecule is
Options
(a) octahedral
(b) trigonal bipyramidal
(c) tetrahedral
(d) pentagonal bipyramidal
Correct Answer:
pentagonal bipyramidal
Explanation:
Number of hybrid orbitals,
H = 1/2 [V + M + A – C]
H = 1/2 [7 + 7 + 0 – 0]
Thus, thehybridisation of IF₇ is sp³d³ and its geometry is pentagonal bypyraminal.
Related Questions: - The number of moles of KMnO₄ that will be needed to react with one mole of
- What is the nature of the bond between B and O in (C₂H₅)₂ OBH₃?
- The enthalphy change for the reaction N₂ + 3H₂ → 2NH₃ is -92.38 kJ at 298K
- The coordination number and oxidation state number of Cr in K₃ Cr (C₂O₄)₃
- In the reaction of H₂O₂ with acidified KMnO₄
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Chemical Bonding and Molecular Structure
(86)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The number of moles of KMnO₄ that will be needed to react with one mole of
- What is the nature of the bond between B and O in (C₂H₅)₂ OBH₃?
- The enthalphy change for the reaction N₂ + 3H₂ → 2NH₃ is -92.38 kJ at 298K
- The coordination number and oxidation state number of Cr in K₃ Cr (C₂O₄)₃
- In the reaction of H₂O₂ with acidified KMnO₄
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Chemical Bonding and Molecular Structure (86)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply