| ⇦ |
| ⇨ |
The root mean square speed of oxygen molecule (O₂) at a certain temperature is v. If the temperature is doubled and the oxygen gas dissociates into atomic oxygen, the rms speed would be
Options
(a) v
(b) √2 v
(c) 2v
(d) 2√2 v
Correct Answer:
2v
Explanation:
The rms speed is given by
v(rms) = √(3RT / M)
[v(rms)]o₂ = √(3RT / M) = √(3RT / M) = v
[v(rms)]o = √[3R(2T) / M] = 2 √(3RT / M) = 2v
Related Questions: - A satellite is launched into a circular orbit of radius R around earth while
- A moving coil galvanometer of resistance 100 Ω is converted to ammeter by a resistance
- The range of voltmeter is 10V and its internal resistance is 50Ω.
- A layer of colourless oil spreads on water surface. White light is incident on it
- When a ball is thrown up vertically with velocity vₒ,it reaches a maximum height
Topics: Behavior of Perfect Gas and Kinetic Theory
(34)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A satellite is launched into a circular orbit of radius R around earth while
- A moving coil galvanometer of resistance 100 Ω is converted to ammeter by a resistance
- The range of voltmeter is 10V and its internal resistance is 50Ω.
- A layer of colourless oil spreads on water surface. White light is incident on it
- When a ball is thrown up vertically with velocity vₒ,it reaches a maximum height
Topics: Behavior of Perfect Gas and Kinetic Theory (34)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply