The root mean square speed of oxygen molecule (O₂) at a certain temperature is v.

The Root Mean Square Speed Of Oxygen Molecule O At Physics Question

The root mean square speed of oxygen molecule (O₂) at a certain temperature is v. If the temperature is doubled and the oxygen gas dissociates into atomic oxygen, the rms speed would be

Options

(a) v
(b) √2 v
(c) 2v
(d) 2√2 v

Correct Answer:

2v

Explanation:

The rms speed is given by
v(rms) = √(3RT / M)
[v(rms)]o₂ = √(3RT / M) = √(3RT / M) = v
[v(rms)]o = √[3R(2T) / M] = 2 √(3RT / M) = 2v

Related Questions:

  1. A drum of radius R and mass M, rolls down without slipping along an inclined plane
  2. Find out the angle of projection, if range is 4 times of maximum height
  3. A moving coil galvanometer of resistance 100 Ω is converted to ammeter by a resistance
  4. In an L-C-R series resonant circuit, the capacitance is changed from C to 4C.
  5. Three resistances 2Ω, 3Ω and 4Ω are connected in parallel. The ratio of currents passing

Topics: Behavior of Perfect Gas and Kinetic Theory (34)
Subject: Physics (2479)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

Be the first to comment

Leave a Reply

Your email address will not be published.


*