| ⇦ | 
| ⇨ |
The root mean square speed of oxygen molecule (O₂) at a certain temperature is v. If the temperature is doubled and the oxygen gas dissociates into atomic oxygen, the rms speed would be
Options
(a) v
(b) √2 v
(c) 2v
(d) 2√2 v
Correct Answer:
2v
Explanation:
The rms speed is given by
v(rms) = √(3RT / M)
[v(rms)]o₂ = √(3RT / M) = √(3RT / M) = v
[v(rms)]o = √[3R(2T) / M] = 2 √(3RT / M) = 2v
Related Questions: - The potential energy of particle in a force field is U = A/r² – b/r, where A and B
- When a bullet of mass 10 g and speed 100 ms⁻¹ penetrates up to distance 1 cm
- In a circuit, 5% of total current passes through a galvanometer. If resistance
- The initial rate of increase of current, when a battery of emf 6 V is connected
- A bar magnet of moment of inertia I is vibrated in a magnetic field of induction
Topics: Behavior of Perfect Gas and Kinetic Theory
(34)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The potential energy of particle in a force field is U = A/r² – b/r, where A and B
- When a bullet of mass 10 g and speed 100 ms⁻¹ penetrates up to distance 1 cm
- In a circuit, 5% of total current passes through a galvanometer. If resistance
- The initial rate of increase of current, when a battery of emf 6 V is connected
- A bar magnet of moment of inertia I is vibrated in a magnetic field of induction
Topics: Behavior of Perfect Gas and Kinetic Theory (34)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply