| ⇦ |
| ⇨ |
The root mean square speed of oxygen molecule (O₂) at a certain temperature is v. If the temperature is doubled and the oxygen gas dissociates into atomic oxygen, the rms speed would be
Options
(a) v
(b) √2 v
(c) 2v
(d) 2√2 v
Correct Answer:
2v
Explanation:
The rms speed is given by
v(rms) = √(3RT / M)
[v(rms)]o₂ = √(3RT / M) = √(3RT / M) = v
[v(rms)]o = √[3R(2T) / M] = 2 √(3RT / M) = 2v
Related Questions: - Electrons in a certain energy level n=n₁, can emit 3 spectral lines. When they
- Two resistors of 6Ω and 9Ω are connected in series to a 120 V source.
- In atom bomb, the reaction which occurs is
- If the rise in height of capillary of two tubes is 6.6 cm and 2.2 cm
- The half life of radium is 1620 yr and its atomic weight is 226 kg per kilo mol.
Topics: Behavior of Perfect Gas and Kinetic Theory
(34)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Electrons in a certain energy level n=n₁, can emit 3 spectral lines. When they
- Two resistors of 6Ω and 9Ω are connected in series to a 120 V source.
- In atom bomb, the reaction which occurs is
- If the rise in height of capillary of two tubes is 6.6 cm and 2.2 cm
- The half life of radium is 1620 yr and its atomic weight is 226 kg per kilo mol.
Topics: Behavior of Perfect Gas and Kinetic Theory (34)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply