| ⇦ |
| ⇨ |
The root mean square speed of oxygen molecule (O₂) at a certain temperature is v. If the temperature is doubled and the oxygen gas dissociates into atomic oxygen, the rms speed would be
Options
(a) v
(b) √2 v
(c) 2v
(d) 2√2 v
Correct Answer:
2v
Explanation:
The rms speed is given by
v(rms) = √(3RT / M)
[v(rms)]o₂ = √(3RT / M) = √(3RT / M) = v
[v(rms)]o = √[3R(2T) / M] = 2 √(3RT / M) = 2v
Related Questions: - Which of the following physical quantities has neither dimensions nor unit
- The internal energy change in a system that has absorbed 2 kcals of heat
- Two rigid bodies A and B rotate with rotational kinetic energies Eᴀ and Eʙ
- A flywheel rotating about a fixed axis has a kinetic energy of 360 J when
- A cycle wheel of radius 4 m completes one revolution in two seconds. Then acceleration
Topics: Behavior of Perfect Gas and Kinetic Theory
(34)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which of the following physical quantities has neither dimensions nor unit
- The internal energy change in a system that has absorbed 2 kcals of heat
- Two rigid bodies A and B rotate with rotational kinetic energies Eᴀ and Eʙ
- A flywheel rotating about a fixed axis has a kinetic energy of 360 J when
- A cycle wheel of radius 4 m completes one revolution in two seconds. Then acceleration
Topics: Behavior of Perfect Gas and Kinetic Theory (34)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply