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The root mean square speed of oxygen molecule (O₂) at a certain temperature is v. If the temperature is doubled and the oxygen gas dissociates into atomic oxygen, the rms speed would be
Options
(a) v
(b) √2 v
(c) 2v
(d) 2√2 v
Correct Answer:
2v
Explanation:
The rms speed is given by
v(rms) = √(3RT / M)
[v(rms)]o₂ = √(3RT / M) = √(3RT / M) = v
[v(rms)]o = √[3R(2T) / M] = 2 √(3RT / M) = 2v
Related Questions: - A spherical drop of mercury having a potential of 2.5 v is obtained as a result
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Topics: Behavior of Perfect Gas and Kinetic Theory
(34)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A spherical drop of mercury having a potential of 2.5 v is obtained as a result
- λ₁ and λ₂ are used to illuminate the slits. β₁ and β₂ are the corresponding fringe
- The phase difference between two points seperated by 0.8 m in a wave of frequency
- Two stones of masses m and 2m are whirled in horizontal circles, the heavier one
- In a double slit experiment, the two slits are 1mm apart and the screen is placed 1 m
Topics: Behavior of Perfect Gas and Kinetic Theory (34)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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