| ⇦ | 
| ⇨ |
The resistance of a carbon resistor of colour code Red-Red Green Silver is (in kΩ)
Options
(a) 2200±5%
(b) 2200±10%
(c) 220±10%
(d) 220±5%
Correct Answer:
2200±10%
Explanation:
Given, Colour coding of resistance = Red, Red, Green, Silver
First band value = 2
Second band value = 2
Third band value = 10⁵
Fourth band value = ± 10%
Now, R = 22 × 10⁵ ± 10% Ω
R = 2200 ± 10% kΩ
Related Questions: - Two points are located at a distance of 10 m and 15 m from the source of oscillation
- In a circuit, the current lags behind the voltage by a phase difference of π/2.
- A small object of uniform density rolls up a curved surface with an initial velocity
- A spherical body of emissivity e=0.6, placed inside a perfectly black body is maintained
- When a ceiling fan is switched off its angular velocity reduces to 50% while
Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two points are located at a distance of 10 m and 15 m from the source of oscillation
- In a circuit, the current lags behind the voltage by a phase difference of π/2.
- A small object of uniform density rolls up a curved surface with an initial velocity
- A spherical body of emissivity e=0.6, placed inside a perfectly black body is maintained
- When a ceiling fan is switched off its angular velocity reduces to 50% while
Topics: Current Electricity (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply