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The ratio of the weight of a man in a stationary lift and when it is moving downwards with uniform acceleration a is 3:2,then the value of a is
Options
(a) 3/2 g
(b) g/3
(c) g
(d) 2/3g
Correct Answer:
g/3
Explanation:
Weight when stationary = mg
Weight when moving downwards = m(g-a)
3/2 = mg/m(g-a)
3g – 3a = 2g
⇒ a = g/3
Related Questions: - A and B are two vectors and θ is the angle between them ,if |A x B|=√3(A.B),the value of θ
- A concave lens of focal length f forms an image which is 1/3 times the size
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A and B are two vectors and θ is the angle between them ,if |A x B|=√3(A.B),the value of θ
- A concave lens of focal length f forms an image which is 1/3 times the size
- The energy released by the fission of one uranium atom is 200 MeV.
- Choose the correct statement
- As a result of interference of two coherent sources of light, energy is
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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