| ⇦ | 
| ⇨ |
The ratio of the weight of a man in a stationary lift and when it is moving downwards with uniform acceleration a is 3:2,then the value of a is
Options
(a) 3/2 g
(b) g/3
(c) g
(d) 2/3g
Correct Answer:
g/3
Explanation:
Weight when stationary = mg
Weight when moving downwards = m(g-a)
3/2 = mg/m(g-a)
3g – 3a = 2g
⇒ a = g/3
Related Questions: - In stretching a spring by 2 cm, energy stored is given by U. Had is been stretched
- Consider a compound slab consisting of two different materials having equal thickness
- The value of coefficient of volume expansion of glycerin is 5 x 10⁻⁴ k⁻¹.
- A current I ampere flows along the inner conductor of a co-axial cable and returns
- The induced emf in a coil of 10 H inductance in which current varies
Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In stretching a spring by 2 cm, energy stored is given by U. Had is been stretched
- Consider a compound slab consisting of two different materials having equal thickness
- The value of coefficient of volume expansion of glycerin is 5 x 10⁻⁴ k⁻¹.
- A current I ampere flows along the inner conductor of a co-axial cable and returns
- The induced emf in a coil of 10 H inductance in which current varies
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply