⇦ | ⇨ |
The ratio of the weight of a man in a stationary lift and when it is moving downwards with uniform acceleration a is 3:2,then the value of a is
Options
(a) 3/2 g
(b) g/3
(c) g
(d) 2/3g
Correct Answer:
g/3
Explanation:
Weight when stationary = mg
Weight when moving downwards = m(g-a)
3/2 = mg/m(g-a)
3g – 3a = 2g
⇒ a = g/3
Related Questions:
- A tuning fork of frequency 512 Hz makes 4 beats per second with the vibrating string
- An object is placed 30 cm away from a convex lens of focal length 10 cm and a sharp
- If (range)² is 48 times (maximum height)², then angle of projection is
- Two particles A and B, move with constant velocities V₁ and V₂. At the initial
- A body projected vertically from the earth reaches a height equal to earth’s radius
Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply