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The ratio of the weight of a man in a stationary lift and when it is moving downwards with uniform acceleration a is 3:2,then the value of a is
Options
(a) 3/2 g
(b) g/3
(c) g
(d) 2/3g
Correct Answer:
g/3
Explanation:
Weight when stationary = mg
Weight when moving downwards = m(g-a)
3/2 = mg/m(g-a)
3g – 3a = 2g
⇒ a = g/3
Related Questions: - The wave described by y = 0.25 sin (10 2πx – 2πt), where x and y are in meters
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The wave described by y = 0.25 sin (10 2πx – 2πt), where x and y are in meters
- The value of workdone for rotating a magnet of magnetic moment M by an angle θ in external
- Which of the following figures represent the variation of particle momentum
- At absolute temperature, the kinetic energy of the molecules
- A galvanometer of resistance 50Ω is connected to a battery of 3 V along with a resistance
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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