| ⇦ |
| ⇨ |
The ratio of the difference in energy between first and second Bohr orbit to that between the second and the third Bohr orbit is
Options
(a) 1/2
(b) 1/3
(c) 4/9
(d) 27/5
Correct Answer:
27/5
Explanation:
E₁ – E₂ = 1312 x Z²(1/1² – 1/2²)
= 1312 x Z²(3/4)
E₂ – E₃ = 1312 x Z²(1/2² – 1/3²)
= 1312 x Z²(5/36)
From eqs. (i) and (ii)
E₁ – E₂ / E₂ – E₃ = 3 x 26 / 4 x 5 = 27/5
Related Questions: - Which of the following is dihydric alcohol
- Which of the following compounds possesses the C-H bond with the lowest bond dissociation
- Mass of one atom of X is 2.66 x 10⁻²³ g, then its 32 g is equal to
- The correct statement regarding defects in crystalline solids is
- Baeyer’s reagent is used in the laboratory for
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Structure of Atom
(90)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which of the following is dihydric alcohol
- Which of the following compounds possesses the C-H bond with the lowest bond dissociation
- Mass of one atom of X is 2.66 x 10⁻²³ g, then its 32 g is equal to
- The correct statement regarding defects in crystalline solids is
- Baeyer’s reagent is used in the laboratory for
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Structure of Atom (90)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply