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The ratio of speed of an electron in ground state in Bohr’s first orbit of hydrogen atom to velocity of light in air (c ) is
Options
(a) e²/2ε₀hc
(b) 2e²ε₀/hc
(c) e³/2ε₀hc
(d) 2ε₀hc/e²
Correct Answer:
e²/2ε₀hc
Explanation:
Velocity of electron in nᵗʰ orbit = αcz / n
where α = (e²/4πε₀) [1 / c(h/π)] = e²/2ε₀hc
v / c = αz / n = (e² × 1) / 2ε₀hc × 1 = e²/2ε₀hc
Related Questions: - A charge of 40 µC is given to a capacitor having capacitance C=10 µF
- A 1Ω resistance in series with an ammeter is balanced by 75 cm of potentiometer wire
- Number of electrons in one mC charge, given e=1.6×10⁻¹⁹ C, will be
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Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A charge of 40 µC is given to a capacitor having capacitance C=10 µF
- A 1Ω resistance in series with an ammeter is balanced by 75 cm of potentiometer wire
- Number of electrons in one mC charge, given e=1.6×10⁻¹⁹ C, will be
- For photoelectric emission from certain metal the cut-off frequency is v
- Equal currents are passing through two very long and straight parallel wires
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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