| ⇦ | 
| ⇨ |
The ratio of speed of an electron in ground state in Bohr’s first orbit of hydrogen atom to velocity of light in air (c ) is
Options
(a) e²/2ε₀hc
(b) 2e²ε₀/hc
(c) e³/2ε₀hc
(d) 2ε₀hc/e²
Correct Answer:
e²/2ε₀hc
Explanation:
Velocity of electron in nᵗʰ orbit = αcz / n
where α = (e²/4πε₀) [1 / c(h/π)] = e²/2ε₀hc
v / c = αz / n = (e² × 1) / 2ε₀hc × 1 = e²/2ε₀hc
Related Questions:
- Two identical cells of the same e.m.f. and same internal resistance
- The ratio of the weight of a man in a stationary lift and when it is moving downwards
- What is the value of incidence L for which the current is maximum in a series LCR
- For high frequency a capacity offers
- An inductor coil is connected to a 12 V battery and drawing a current 24 A. This coil
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply