| ⇦ | 
| ⇨ |
The ratio of area covered by second orbital to the first orbital is
Options
(a) 1 : 2
(b) 1 : 16
(c) 8 : 1
(d) 16 : 1
Correct Answer:
16 : 1
Explanation:
r(n) ∝ n² ; A(n) ∝ n⁴.
A₂ / A₁ = n₂⁴ / n⁴₁ = 2⁴ / 1⁴ = 16 / 1.
Related Questions: - Phenolic carboxylic acids may be prepared by
- Formation of methyl tertiary butyl ether by the reaction of sodium tertiary
- The recycling of plastic is done by
- In the cyanide ion, the formal negative charge is on
- Dead burnt plaster is
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Structure of Atom
(90)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Phenolic carboxylic acids may be prepared by
- Formation of methyl tertiary butyl ether by the reaction of sodium tertiary
- The recycling of plastic is done by
- In the cyanide ion, the formal negative charge is on
- Dead burnt plaster is
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Structure of Atom (90)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply