The rate constant of the reaction A → B is 0.6 ˣ 10⁻³ mol per second.

The Rate Constant Of The Reaction A B Is Chemistry Question

The rate constant of the reaction A → B is 0.6 ˣ 10⁻³ mol per second. If the concentration of A is 5 M, then concentration of B after 20 minutes is

Options

(a) 3.60 M
(b) 0.36 M
(c) 0.72 M
(d) 1.08 M

Correct Answer:

0.72 M

Explanation:

No explanation available. Be the first to write the explanation for this question by commenting below.

Related Questions:

  1. An organic acid without a carboxylic acid group is
  2. Which is not the property transition elements
  3. D(+)-glucose reacts with hydroxyl amine and yields an oxime.
  4. The number of acidic protons in H₃PO₃ are
  5. Carbon percentage is maximum in

Topics: Electrochemistry and Chemical Kinetics (87)
Subject: Chemistry (2512)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

2 Comments on The rate constant of the reaction A → B is 0.6 ˣ 10⁻³ mol per second.

  1. Reaction is of zero order as the unit of rate constant is mol L⁻¹ S⁻¹
    .·. Concentration of B =k × t =0.6×10⁻³ × 20 × 60 = 0.72 M

  2. Let at time t=0 (A)= a and (B)=0
    At time t=(20*60)sec (A)= (a-x) and (B)=x then
    For 1st order reaction
    (A’) =(A) – kt
    : a-x = a – 0.6*10-3*20*60
    Solving it will give
    X= 0.72 M

Leave a Reply

Your email address will not be published.


*