| ⇦ |
| ⇨ |
The radius of orbit of a planet is two times that of the earth. The time period of planet is
Options
(a) 4.2 year
(b) 2.8 year
(c) 5.6 year
(d) 8.4 year
Correct Answer:
2.8 year
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - If threshold wevelength for sodium is 6800 Å, the work function will be
- In a water fall, the water falls from a height of 100 m. If the entire kinetic energy
- A particle is released from rest from a tower of height h, i.e,t₁ : t₂ : t₃ is
- A and B are two metals with threshold frequencies 1.8 x 10¹⁴ Hz and 2.2 x 10¹⁴ Hz.
- A heavy small sized sphere is suspended by a string of length l.The sphere rotates
Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If threshold wevelength for sodium is 6800 Å, the work function will be
- In a water fall, the water falls from a height of 100 m. If the entire kinetic energy
- A particle is released from rest from a tower of height h, i.e,t₁ : t₂ : t₃ is
- A and B are two metals with threshold frequencies 1.8 x 10¹⁴ Hz and 2.2 x 10¹⁴ Hz.
- A heavy small sized sphere is suspended by a string of length l.The sphere rotates
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

By keplers third law (T1^2/T2^2)=(R1^3/R2^3)
so,
x^2/1^2=(2r)^3/r^3
x^2=8
x=2.8