| ⇦ |
| ⇨ |
The radius of orbit of a planet is two times that of the earth. The time period of planet is
Options
(a) 4.2 year
(b) 2.8 year
(c) 5.6 year
(d) 8.4 year
Correct Answer:
2.8 year
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - If a body is rolling on the surface, its total energy will be
- A force F=ai+3j+6k is acting at a point r=2i-6j-12k. The value of α for
- A block of mass 4 kg is kept on a rough horizontal surface.The coefficient of static
- The de-Broglie wavelength of an electron in the first Bohr orbit is
- Radius of orbit of satellite of earth is R. Its kinetic energy is proportional to
Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If a body is rolling on the surface, its total energy will be
- A force F=ai+3j+6k is acting at a point r=2i-6j-12k. The value of α for
- A block of mass 4 kg is kept on a rough horizontal surface.The coefficient of static
- The de-Broglie wavelength of an electron in the first Bohr orbit is
- Radius of orbit of satellite of earth is R. Its kinetic energy is proportional to
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

By keplers third law (T1^2/T2^2)=(R1^3/R2^3)
so,
x^2/1^2=(2r)^3/r^3
x^2=8
x=2.8