| ⇦ |
| ⇨ |
The radius of orbit of a planet is two times that of the earth. The time period of planet is
Options
(a) 4.2 year
(b) 2.8 year
(c) 5.6 year
(d) 8.4 year
Correct Answer:
2.8 year
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Two sources P and Q produce notes of frequency 660 Hz each.
- A capacitor of 10 µF charged upto 250 volt is connected in parallel with another
- The ratio of radii of planets A and B is K₁ and ratio of accelerations
- The radius of curvature of a convave mirror is 24 cm and the imager is magnified
- If the rise in height of capillary of two tubes is 6.6 cm and 2.2 cm
Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two sources P and Q produce notes of frequency 660 Hz each.
- A capacitor of 10 µF charged upto 250 volt is connected in parallel with another
- The ratio of radii of planets A and B is K₁ and ratio of accelerations
- The radius of curvature of a convave mirror is 24 cm and the imager is magnified
- If the rise in height of capillary of two tubes is 6.6 cm and 2.2 cm
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

By keplers third law (T1^2/T2^2)=(R1^3/R2^3)
so,
x^2/1^2=(2r)^3/r^3
x^2=8
x=2.8