| ⇦ |
| ⇨ |
The radius of gyration of a solid sphere of radius r about a certain axis is r. The distance of this axis from the centre of the sphere is
Options
(a) r
(b) 0.5r
(c) √(0.6)r
(d) √(0.4)r
Correct Answer:
√(0.6)r
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - For CE transistor amplifier, the audio signal voltage across the collector resistance
- In insulators (CB is Conduction Band and VB is Valence Band)
- The angle between the dipole moment and electric field at any point on the equatoria
- Source S₁ is producing, 10¹⁵ photons per second of wavelength 5000Å
- A wire of length 1 m is moving at a speed of 2 ms⁻¹ perpendicular to its length
Topics: Motion of system of Particles and Rigid Body
(73)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- For CE transistor amplifier, the audio signal voltage across the collector resistance
- In insulators (CB is Conduction Band and VB is Valence Band)
- The angle between the dipole moment and electric field at any point on the equatoria
- Source S₁ is producing, 10¹⁵ photons per second of wavelength 5000Å
- A wire of length 1 m is moving at a speed of 2 ms⁻¹ perpendicular to its length
Topics: Motion of system of Particles and Rigid Body (73)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Using parallel axis theorem ,
I =Icm(about the centre of mass) + M(mass of the sphere)h2. where h is the required distance of the axis from centre of sphere
MK2 = 2/5 MR2. + Mh2
K2= 2R2/5 + h2
R2 = 2R2/5. + h2. (given that. K=R. )
3R2/5 = h2
Which gives h=√3/5R2
h=√0.6. R. (Answer)