| ⇦ | 
| ⇨ |
The radius of gyration of a solid sphere of radius r about a certain axis is r. The distance of this axis from the centre of the sphere is
Options
(a) r
(b) 0.5r
(c) √(0.6)r
(d) √(0.4)r
Correct Answer:
√(0.6)r
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Zener diode is used
- A wire of length 1 m is moving at a speed of 2 ms⁻¹ perpendicular to its length
- The force F acting on a particle of mass m is indicated by the force-time graph
- A particle has initial velocity (2i⃗+3j⃗) and acceleration (0.3i⃗+0.2j⃗). The magnitude
- A astronomical telescope has objective and eye-piece of focal lengths
Topics: Motion of system of Particles and Rigid Body
(73)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Zener diode is used
- A wire of length 1 m is moving at a speed of 2 ms⁻¹ perpendicular to its length
- The force F acting on a particle of mass m is indicated by the force-time graph
- A particle has initial velocity (2i⃗+3j⃗) and acceleration (0.3i⃗+0.2j⃗). The magnitude
- A astronomical telescope has objective and eye-piece of focal lengths
Topics: Motion of system of Particles and Rigid Body (73)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Using parallel axis theorem ,
I =Icm(about the centre of mass) + M(mass of the sphere)h2. where h is the required distance of the axis from centre of sphere
MK2 = 2/5 MR2. + Mh2
K2= 2R2/5 + h2
R2 = 2R2/5. + h2. (given that. K=R. )
3R2/5 = h2
Which gives h=√3/5R2
h=√0.6. R. (Answer)