| ⇦ | 
| ⇨ |
The radius of curvature of a concave mirror is 24 cm and the imager is magnified by 1.5 times. The object distance is
Options
(a) 20 cm
(b) 8 cm
(c) 16 cm
(d) 24 cm
Correct Answer:
20 cm
Explanation:
R = -24 cm, f = -12 cm, m = 1.5
(1 / v) + (1 / u) = 1 / f
.·. u = 20 cm.
Related Questions: - In a vaccum triode the function of grid voltage is
- An object moving with a speed of 6.25 m/s, is deaccelerated at a rate given by
- The 6563 Å line emitted by hydrogen atom in a star is found to be red shifted by 5Å
- A uniform rod of length l is placed with one end in contact with the horizontal
- The potential energy of a simple harmonic oscillator when the particle is half way
Topics: Ray Optics
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In a vaccum triode the function of grid voltage is
- An object moving with a speed of 6.25 m/s, is deaccelerated at a rate given by
- The 6563 Å line emitted by hydrogen atom in a star is found to be red shifted by 5Å
- A uniform rod of length l is placed with one end in contact with the horizontal
- The potential energy of a simple harmonic oscillator when the particle is half way
Topics: Ray Optics (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
given that
R=24 cm
f=R/2=24/2=12 cm
and m= -v/u = -3/2……..(1)
v=3/2 u ………….(2)
from mirror equation,
1/v+1/u=1/f…………….(3)
putting the value of f and v in equation (3) we get,
2/3u+1/u=1/12
3u=60
u=20 cm