⇦ | ⇨ |
The radius of curvature of a concave mirror is 24 cm and the imager is magnified by 1.5 times. The object distance is
Options
(a) 20 cm
(b) 8 cm
(c) 16 cm
(d) 24 cm
Correct Answer:
20 cm
Explanation:
R = -24 cm, f = -12 cm, m = 1.5
(1 / v) + (1 / u) = 1 / f
.·. u = 20 cm.
Related Questions: - The acceleration due to gravity at a place is π² m/sec². Then the time period
- On adjusting the P-N junction diode in forward bias,
- The potential differences across the resistance, capacitance and inductance
- If light emitted from sodium bulb is passed through sodium vapour,
- Electric field at a point of distance r from a uniformly charged wire of infinite
Topics: Ray Optics
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The acceleration due to gravity at a place is π² m/sec². Then the time period
- On adjusting the P-N junction diode in forward bias,
- The potential differences across the resistance, capacitance and inductance
- If light emitted from sodium bulb is passed through sodium vapour,
- Electric field at a point of distance r from a uniformly charged wire of infinite
Topics: Ray Optics (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
given that
R=24 cm
f=R/2=24/2=12 cm
and m= -v/u = -3/2……..(1)
v=3/2 u ………….(2)
from mirror equation,
1/v+1/u=1/f…………….(3)
putting the value of f and v in equation (3) we get,
2/3u+1/u=1/12
3u=60
u=20 cm