| ⇦ |
| ⇨ |
The pressure and temperature of 4 dm³ of carbon dioxide gas are doubled. Then the volume of carbon dioxide gas would be
Options
(a) 2 dm³
(b) 3 dm³
(c) 4 dm³
(d) 8 dm³
Correct Answer:
4 dm³
Explanation:
P₁ = P , V₁ = 4 dm³, T₁ = T. P₂ = 2P, V₂ = ?, T₂ = 2T. From gas equation, P₁V₁ / T₁ = P₂V₂ / T₂ ⇒ P * 4 / T = 2P * V / 2T. ⇒ V = 4dm³.
Related Questions: - Copper occurs naturally as Cu-63 and Cu-65. Given Atomic Weight
- The oxidation states of Mn in MnSO₄,MnO₂,K₂MnO₄ and KMnO₄ are respectively
- The number of sigma and pi-bonds in but-1-ene-3-yne are
- The number of water molecules in gypsum and in plaster of paris are respectively
- Colligative properties of solution are those properties which depend on the
Topics: States of Matter Gases and Liquids
(80)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Copper occurs naturally as Cu-63 and Cu-65. Given Atomic Weight
- The oxidation states of Mn in MnSO₄,MnO₂,K₂MnO₄ and KMnO₄ are respectively
- The number of sigma and pi-bonds in but-1-ene-3-yne are
- The number of water molecules in gypsum and in plaster of paris are respectively
- Colligative properties of solution are those properties which depend on the
Topics: States of Matter Gases and Liquids (80)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply