The potential difference that must be applied to stop the fastest photoelectrons

The potential difference that must be applied to stop the fastest photoelectrons emitted by a nickel surface, having work function 5.01 eV, when ultraviolet light of 200 nm falls on it, must be:

Options

(a) 2.4 V
(b) – 1.2 V
(c) – 2.4 V
(d) 1.2 V

Correct Answer:

1.2 V

Explanation:

Kₘₐₓ = hc / – W = hc / λ – 5.01
= 12375 / λ(in Å) – 5.01
12375 / 2000 – 5.01 = 6.1875 – 5.01 = 1.17775
= 1.2 V

admin:

Related Questions

  1. A sound absorber attenuates the sound level by 20 dB. The intensity decreases
  2. A pure semiconductor behaves slightly as a conductor at
  3. A solid body rotates about a stationary axis, so that its angular velocity
  4. Sodium and copper have work function 2.3 eV and 4.5 eV respectively
  5. Figure below shows two paths that may be taken by a gas to go from a state A