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The potential difference that must be applied to stop the fastest photoelectrons emitted by a nickel surface, having work function 5.01 eV, when ultraviolet light of 200 nm falls on it, must be:
Options
(a) 2.4 V
(b) – 1.2 V
(c) – 2.4 V
(d) 1.2 V
Correct Answer:
1.2 V
Explanation:
Kₘₐₓ = hc / – W = hc / λ – 5.01
= 12375 / λ(in Å) – 5.01
12375 / 2000 – 5.01 = 6.1875 – 5.01 = 1.17775
= 1.2 V
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Cohesive force is experienced between
- If two bodies are projected at 30⁰ and 60⁰ respectively with the same velocity, then
- If emf induced in a coil is 2 V by changing the current in it from 8 A to 6 A
- Before using the tangent galvanometer, its coil is set in
- If an electron in a hydrogen atom jumps from the 3rd orbit to the 2nd orbit, it emits
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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