⇦ | ⇨ |
The point of suspension λ of a simple pendulum with normal time period T₁ is moving upward according to equation y=kt² where k=1 m/s². If new time period is T² the ratio T₁²/T₂² will be
Options
(a) (2/3)
(b) (5/6)
(c) (6/5)
(d) (3/2)
Correct Answer:
(6/5)
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The time period of bar magnet is doubled when magnetic field is reduced
- For the radioactive nuclei that undergo either α or β decay, which one
- If two electric bulbs have 40 W and 60 W ratings at 220 V, then the ratio
- A thin semicircular conducting ring (PQR) of radius r is falling with its plane
- A thermoelectric refrigerator works on
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The time period of bar magnet is doubled when magnetic field is reduced
- For the radioactive nuclei that undergo either α or β decay, which one
- If two electric bulbs have 40 W and 60 W ratings at 220 V, then the ratio
- A thin semicircular conducting ring (PQR) of radius r is falling with its plane
- A thermoelectric refrigerator works on
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply