| ⇦ | 
| ⇨ |
The phase difference between two points seperated by 0.8 m in a wave of frequency 120 Hz is 0.5 π. The wave velocity is
Options
(a) 144 m/s
(b) 256 m/s
(c) 384 m/s
(d) 720 m/s
Correct Answer:
384 m/s
Explanation:
Phase difference = 2π/λ × Path difference
0.5π = 2π/λ × 0.8 m or λ = (2π × 0.8 m) / 0.5π = 3.2 m
Velocity v = frequency (ʋ) × Wavelength (λ)
= 120 Hz × 3.2 m = 384 m/s.
Related Questions: - During production of cathode ray
- Two slits in Young’s experiment have widths in the ratio 1:25. The ratio of intensity
- A 220 volt and 1000 watt bulb is connected across a 110 volt mains supply.
- The coefficient of mutual inductance of two coils is 6 mH. If the current flowing
- The refracting angle of a prism is A and refractive index of the material of the prism
Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- During production of cathode ray
- Two slits in Young’s experiment have widths in the ratio 1:25. The ratio of intensity
- A 220 volt and 1000 watt bulb is connected across a 110 volt mains supply.
- The coefficient of mutual inductance of two coils is 6 mH. If the current flowing
- The refracting angle of a prism is A and refractive index of the material of the prism
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply