The phase difference between the flux linked with a coil rotating in a uniform

⇦

⇨

The phase difference between the flux linked with a coil rotating in a uniform magnetic field and induced emf produced in it is

Options

(a) π/2
(b) π/3
(c) (-π/6)
(d) π

Correct Answer:

π/2

Explanation:

The flux ɸ = B.A = |B| |A| cos θ

Also, induced emf, ε = – (dɸ / dt) = (d |B| |A| cos θ) / dt

= – |B| |A| [d cos θ / dt] = |B| |A| sin θ. ω

ε = BA ω cos [θ – (π / 2)]

Related Questions:

1. The radius of a planet is twice the radius of earth. Both have almost
2. Zenor breakdown in a semiconductor diode occurs when
3. A parallel beam of light of wavelength λ is incident normally on a narrow slit
4. A generator at a utility company produces 100 A of current at 4000 V. The voltage
5. A single slit Fraunhogger diffraction pattern is formed with white light.

Topics: Electromagnetic Induction (76)
Subject: Physics (2479)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends