⇦ | ⇨ |
The phase difference between the flux linked with a coil rotating in a uniform magnetic field and induced emf produced in it is
Options
(a) π/2
(b) π/3
(c) (-π/6)
(d) π
Correct Answer:
π/2
Explanation:
The flux ɸ = B.A = |B| |A| cos θ
Also, induced emf, ε = – (dɸ / dt) = (d |B| |A| cos θ) / dt
= – |B| |A| [d cos θ / dt] = |B| |A| sin θ. ω
ε = BA ω cos [θ – (π / 2)]
Related Questions: - A block of mass m1 rests on a horizontal table. A light string connected
- A train moving at a speed of 220 ms⁻¹ towards a stationary object
- A vibrating string of certain length l under a tension T resonates with a mode
- A block of mass M is attached to the lower end of a vertical spring
- The equation of state for 5 g of oxygen at a pressure P and temperature T,
Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A block of mass m1 rests on a horizontal table. A light string connected
- A train moving at a speed of 220 ms⁻¹ towards a stationary object
- A vibrating string of certain length l under a tension T resonates with a mode
- A block of mass M is attached to the lower end of a vertical spring
- The equation of state for 5 g of oxygen at a pressure P and temperature T,
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply