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The pH value of 0.02 M ammonia solution, which is 5% ionised, will be
Options
(a) 7
(b) 5
(c) 2
(d) 11
Correct Answer:
11
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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[H+]=C× ionisation constant
= 0.02×5÷100
= 1/1000
pOH=3
pH= 14-3= 11