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The particle executing simple harmonic motion has a kinetic energy K₀ cos²ωt. The maximum values of the potential energy and the total energy are respectively
Options
(a) K₀/2 and K₀
(b) K₀ and 2 K₀
(c) K₀ and K₀
(d) 0 and 2 K₀
Correct Answer:
K₀ and K₀
Explanation:
Kinetic energy + Potential energy = total energy
When kinetic energy is maximum, potential energy is zero and vice versa.
.·. Maximum potential energy = total energy
0 + K₀ = K₀
(K.E + P.E = Total energy) .
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Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A coin of mass m and radius r having moment of inertia I about the axis passes
- A wire of length 2 m is made from 10 cm³ of copper. A force F is applied so that
- In the reaction ₉₂U²³⁴→₈₇Y²²², how many α-particle and β-particles are emitted
- A fringe width of a certain interference pattern is β=0.002 cm. What is the distance
- 300j work is done in sliding a 2kg block up an inclined plane of height 10m
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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