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The particle executing simple harmonic motion has a kinetic energy K₀ cos²ωt. The maximum values of the potential energy and the total energy are respectively
Options
(a) K₀/2 and K₀
(b) K₀ and 2 K₀
(c) K₀ and K₀
(d) 0 and 2 K₀
Correct Answer:
K₀ and K₀
Explanation:
Kinetic energy + Potential energy = total energy
When kinetic energy is maximum, potential energy is zero and vice versa.
.·. Maximum potential energy = total energy
0 + K₀ = K₀
(K.E + P.E = Total energy) .
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Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A beam of light of λ=600 nm from a distant source falls on a single slit 1 mm wide
- In the given figure, a diode D is connected to an external resistance R=100 Ω
- The number of significant figures in 0.06900
- Two wires of equal length and equal diameter and having resistivities ρ₁ and ρ₂
- The difference in the variation of resistance with temperature in a metal
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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