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The oxidation states of sulphur in the anions : SO₃²⁻,S₂O₄²⁻ and S₂O₆²⁻ follow the order
Options
(a) S₂O₄²⁻ < SO₃²⁻ < S₂O₆²⁻
(b) SO₃²⁻ < S₂O₄²⁻ < S₂O₆²⁻
(c) S₂O₄²⁻ < S₂O₆²⁻ < SO₃²⁻
(d) S₂O₆²⁻ < S₂O₄²⁻ < SO₃²⁻
Correct Answer:
S₂O₄²⁻ < SO₃²⁻ < S₂O₆²⁻
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Reason of lanthanoid contraction is
- The oxidation of benzene by V₂O₅ in the presence of air produces
- For azimuthal quantum number l= 3,the maximum number of electrons will be
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Topics: Hydrogen and Redox Reactions
(174)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Reason of lanthanoid contraction is
- The oxidation of benzene by V₂O₅ in the presence of air produces
- For azimuthal quantum number l= 3,the maximum number of electrons will be
- Acetylene, on reacting with formaldehyde under high pressure, gives
- The mixture of n-hexane and n-heptane is an example of
Topics: Hydrogen and Redox Reactions (174)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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