| ⇦ | 
| ⇨ |
The original temperature of a black body is 727⁰C. The temperature at which this black body must be raised so as to double the total radiant energy is
Options
(a) 971 K
(b) 1190 K
(c) 2001 K
(d) 1458 K
Correct Answer:
1190 K
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - At what angle should the two forces 2P and √2 P act,so that the resultant force is P√10?
- An electron moves on a straight line path XY as shown. The abcd is a coil adjacent
- A short circuited coil is placed in a magnetic field varying with time. Electrical
- Two balls are dropped from heights h and 2h respectively. The ratio of times
- The unit of electric permittivity is
Topics: Properties of Bulk Matter
(130)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- At what angle should the two forces 2P and √2 P act,so that the resultant force is P√10?
- An electron moves on a straight line path XY as shown. The abcd is a coil adjacent
- A short circuited coil is placed in a magnetic field varying with time. Electrical
- Two balls are dropped from heights h and 2h respectively. The ratio of times
- The unit of electric permittivity is
Topics: Properties of Bulk Matter (130)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply