| ⇦ |
| ⇨ |
The original temperature of a black body is 727⁰C. The temperature at which this black body must be raised so as to double the total radiant energy is
Options
(a) 971 K
(b) 1190 K
(c) 2001 K
(d) 1458 K
Correct Answer:
1190 K
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The velocity of electromagnetic radiation in a medium of permittivity ε₀
- A nucleus at rest splits into two nuclear parts having radii in the ratio 1:2.
- Two bulbs 60 W and 100 W designed for voltage 220 V are connected in series
- A man measures time period of a pendulum(T) in stationary lift. If the lift moves upwards
- If X=3YZ², find dimensions of Y if X and Z are the dimensions of capacity
Topics: Properties of Bulk Matter
(130)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The velocity of electromagnetic radiation in a medium of permittivity ε₀
- A nucleus at rest splits into two nuclear parts having radii in the ratio 1:2.
- Two bulbs 60 W and 100 W designed for voltage 220 V are connected in series
- A man measures time period of a pendulum(T) in stationary lift. If the lift moves upwards
- If X=3YZ², find dimensions of Y if X and Z are the dimensions of capacity
Topics: Properties of Bulk Matter (130)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply