| ⇦ | 
| ⇨ |
The original temperature of a black body is 727⁰C. The temperature at which this black body must be raised so as to double the total radiant energy is
Options
(a) 971 K
(b) 1190 K
(c) 2001 K
(d) 1458 K
Correct Answer:
1190 K
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The unit of permitivity of free space, ε₀ is
- In Young’s double slit experiment the distance between the slits and the screen
- The dimensional formula for Young’s modulus is
- A particle moving along X-axis has acceleration f,at time t given by f=fₒ(1- t/T)
- If two bodies are projected at 30⁰ and 60⁰ respectively with the same velocity, then
Topics: Properties of Bulk Matter
(130)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The unit of permitivity of free space, ε₀ is
- In Young’s double slit experiment the distance between the slits and the screen
- The dimensional formula for Young’s modulus is
- A particle moving along X-axis has acceleration f,at time t given by f=fₒ(1- t/T)
- If two bodies are projected at 30⁰ and 60⁰ respectively with the same velocity, then
Topics: Properties of Bulk Matter (130)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply