| ⇦ | 
| ⇨ |
The original temperature of a black body is 727⁰C. The temperature at which this black body must be raised so as to double the total radiant energy is
Options
(a) 971 K
(b) 1190 K
(c) 2001 K
(d) 1458 K
Correct Answer:
1190 K
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A beam of light consisting of red, green and blue colours is incident on a right
- The magnetic flux linked with a coil at any instant t is given by ?, find emf
- A small part of the rim of a fly wheel breaks off while it is rotating at a constant
- A spring when stretched by 2mm containing energy 4 J. If it is stretched
- At what angle should the two forces 2P and √2 P act,so that the resultant force is P√10?
Topics: Properties of Bulk Matter
(130)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A beam of light consisting of red, green and blue colours is incident on a right
- The magnetic flux linked with a coil at any instant t is given by ?, find emf
- A small part of the rim of a fly wheel breaks off while it is rotating at a constant
- A spring when stretched by 2mm containing energy 4 J. If it is stretched
- At what angle should the two forces 2P and √2 P act,so that the resultant force is P√10?
Topics: Properties of Bulk Matter (130)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply