The orbital angular momentum of a p-electron is given as :

⇦

⇨

The orbital angular momentum of a p-electron is given as :

Options

(a) h/(√2π)
(b) √3 x (h/2π)
(c) √(3/2) x h/π
(d) √6 x h/2π

Correct Answer:

h/(√2π)

Explanation:

Orbital Angular Momentum = h/(2π) x √(l(l+1)). For p orbital, l=1. so => h/(2π) x √2 =? h/(√2π)

Related Questions:

1. The number of spherical nodes in 3p orbitals are
2. The structure of XeOF₄ is
3. Which is purified by steam distillation
4. Oxidation number of carbon in CH₂Cl₂ is
5. The bond angle of sp² – hybrid orbital is

Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Structure of Atom (90)
Subject: Chemistry (2512)

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