| ⇦ | 
| ⇨ |
The number of photons of wavelength of 540 nm emitted per second by an electric bulb of power 100 W is (given h=6×10⁻³⁴ J-s)
Options
(a) 100
(b) 1000
(c) 3×10²⁰
(d) 3×10¹⁸
Correct Answer:
3×10²⁰
Explanation:
Power = nhc / ( × t)
⇒ 100 = [n × (6 × 10⁻³⁴) × (3 × 10⁸)] / (540 × 10⁹ × 1)
⇒ n × 18 × 10⁻²⁶ / 540 × 10⁻⁹ = 100
⇒ n = 100 × 540 × 10⁻⁹ / 18 × 10⁻²⁶ = 3 x 10²⁰
Related Questions: - The pair of quantities having same dimensions is
- A body is rolling down an inclined plane.If KE of rotation is 40% of KE in a translatory
- The average power dissipated in AC circuit is 2 W. If a current flowing through
- A boat of mass 40 kg is at rest.A dog of mass 4 kg moves in the boat
- Three capacitors 3μF,6μF and 6μF are connected in series to a source of 120V.
Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The pair of quantities having same dimensions is
- A body is rolling down an inclined plane.If KE of rotation is 40% of KE in a translatory
- The average power dissipated in AC circuit is 2 W. If a current flowing through
- A boat of mass 40 kg is at rest.A dog of mass 4 kg moves in the boat
- Three capacitors 3μF,6μF and 6μF are connected in series to a source of 120V.
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply