| ⇦ | 
| ⇨ |
The number of photons of wavelength of 540 nm emitted per second by an electric bulb of power 100 W is (given h=6×10⁻³⁴ J-s)
Options
(a) 100
(b) 1000
(c) 3×10²⁰
(d) 3×10¹⁸
Correct Answer:
3×10²⁰
Explanation:
Power = nhc / ( × t)
⇒ 100 = [n × (6 × 10⁻³⁴) × (3 × 10⁸)] / (540 × 10⁹ × 1)
⇒ n × 18 × 10⁻²⁶ / 540 × 10⁻⁹ = 100
⇒ n = 100 × 540 × 10⁻⁹ / 18 × 10⁻²⁶ = 3 x 10²⁰
Related Questions: - Two parallel long wires carry currents i₁ and i₂ with i₁ > i₂ .
- At place on earth, the vertical component of earth’s magnetic field is √3 times
- On observing light from three different stars P, Q and R, it was found that intensity
- Two planets at mean distances d₁ and d₂ from the sun have their frequencies n₁ and n₂
- A balloon with mass m is descending down with an acceleration a
Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two parallel long wires carry currents i₁ and i₂ with i₁ > i₂ .
- At place on earth, the vertical component of earth’s magnetic field is √3 times
- On observing light from three different stars P, Q and R, it was found that intensity
- Two planets at mean distances d₁ and d₂ from the sun have their frequencies n₁ and n₂
- A balloon with mass m is descending down with an acceleration a
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply